2、Oracle中的Start with...Connect By递归查询
DB2解决方案：用with公共递归表达式来解决。
DB2解决方案：用case条件表达式完成。
Oracle SQL：
-------------------
select t.id
from a_organ t
start with t.id in (select decode(t.organtypecode,
''D'',
t.parent,
''S'',
t.parent,
t.id)
from A_ORGAN
where t.id = 35)
connect by t.parent = prior t.id
DB2 SQL：
-------------------------
WITH FKK(id) as
(select o.id from a_organ o
where o.id=35
UNION ALL
select case x.organtypecode
when ''D'' then x.parent
when ''S'' then x.parent
else x.id
end
from FKK fk, a_organ x
where fk.id=x.parent)
select distinct id from FKK;
|
3、Oracle中的dual表对应DB2中的SYSIBM.SYSDUMMY1表
DB2解决方案：对应于DB2中的 SYSIBM.SYSDUMMY1表
Oracle SQL：
-------------------------
select 15 as ttt from dual
结果：
ttt
-------
15
DB2 SQL：
-------------------------
select 15 as ttt from SYSIBM.SYSDUMMY1
结果：
ttt
-------
15
|
4、日期转换问题
DB2解决方案：有相应的函数
Oracle SQL：
-------------------------
select m.*
from dj_mcdj m
where m.mcqc || '' '' like ''%$P%''
and m.xzqhdm || '' '' like ''%$P%''
and m.hylbdm || '' '' like ''%$P%''
and m.blqsrq >= to_date(''$P'', ''yyyy-mm-dd'')
and m.blqsrq < to_date(''$P'', ''yyyy-mm-dd'')+1
DB2 SQL：
select m.*
from dj_mcdj m
where m.mcqc || '' '' like ''%%''
and m.xzqhdm || '' '' like ''%%%''
and m.hylbdm || '' '' like ''%%%''
and date(m.blqsrq) >= date(''1900-01-01'')
and date(m.blqsrq) < date(''2050-01-01'')+1 day
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